Algebra fifth grade
Introduction :
Algebra fifth grade is the school level math course that uses problem solving situations, physical models and appropriate technology to extend algebraic thinking and engage student reasoning. Algebra fifth grade course begins with a study of variables and expressions as well solving equations and inequalities. The fifth grade students need more concentration in algebra which make the base for upcoming algebra concepts. let us see the problems to algebra fifth grade.
Algebra fifth grade:
Example 1:
Simplify : 3+3x-12(x+2)
Solution:
Here we need to simplify step by step using the order of operations.
3+3x -12(x+2) = 3 + 3x -12x -24
= 3 - x - 24
= -21 - x
= -(x + 21)
Example 2:
Simplify : 7 + 3x - 10(x + 3)
Solution:
Here we need to simplify step by step using the order of operations.
7 + 3x - 10(x + 3) = 7 + 3x - 10x - 30
= 7 - 7x - 30
= -7x - 23.
Example 3:
Simplify : 3(2x-3)-5(3-11x)
Solution:
Here we need to simplify step by step using the order of operations.
3(2x-3)-5(3-11x) = 3(2x-3) - 5(3 - 11x)
= 6x - 9 - 15 + 55x
= 61x -9 - 15
= 61x - 24
Example 4:
Simplify : 2+10(2x-32)
Solution:
Here we need to simplify step by step using the order of operations.
2+10(2x-32) = 2 + 20x - 320
= 20x +2 - 320
= 20x - 318.
Algebra fifth grade:
Example 5:
Evaluate 3x2+1 when x =4
Solution:
Given 3x2+1 when x =4
Here we need to substitute the value of x = 4 in the given equation
3x2+1 = 3 * (4)2 + 1
= 3 * 16 +1
= 48 + 1
= 49.
Example 6:
Evaluate 4(x+1) -2 when x =3
Solution:
Given 4(x+1) - 2 when x =3
Here we need to substitute the value of x = 3 in the given equation
4(x+1) - 2 = 4(3 + 1) - 2
= 4(4) - 2
= 16 - 2
= 14
Example 7:
Evaluate 10(2x+1) -3 when x = 4
Solution:
Given 10(2x+1) - 3 when x = 4
Here we need to substitute the value of x = 4 in the given equation
10(2x+1) - 3 = 20x + 10 - 3
= 20x + 7
Example 8:
Evaluate 6(x+1) -3 when x =5
Solution:
Given 6(x+1) - 3 when x =5
Here we need to substitute value of x = 5 in the given equation
6(x+1) - 3 = 6(5 + 1) - 3
= 6(6) - 3
= 36 - 3
= 33
I like to share this math problems 5th grade and Algebra Variables with you all through my blog.
Algebra fifth grade is the school level math course that uses problem solving situations, physical models and appropriate technology to extend algebraic thinking and engage student reasoning. Algebra fifth grade course begins with a study of variables and expressions as well solving equations and inequalities. The fifth grade students need more concentration in algebra which make the base for upcoming algebra concepts. let us see the problems to algebra fifth grade.
Algebra fifth grade:
Example 1:
Simplify : 3+3x-12(x+2)
Solution:
Here we need to simplify step by step using the order of operations.
3+3x -12(x+2) = 3 + 3x -12x -24
= 3 - x - 24
= -21 - x
= -(x + 21)
Example 2:
Simplify : 7 + 3x - 10(x + 3)
Solution:
Here we need to simplify step by step using the order of operations.
7 + 3x - 10(x + 3) = 7 + 3x - 10x - 30
= 7 - 7x - 30
= -7x - 23.
Example 3:
Simplify : 3(2x-3)-5(3-11x)
Solution:
Here we need to simplify step by step using the order of operations.
3(2x-3)-5(3-11x) = 3(2x-3) - 5(3 - 11x)
= 6x - 9 - 15 + 55x
= 61x -9 - 15
= 61x - 24
Example 4:
Simplify : 2+10(2x-32)
Solution:
Here we need to simplify step by step using the order of operations.
2+10(2x-32) = 2 + 20x - 320
= 20x +2 - 320
= 20x - 318.
Algebra fifth grade:
Example 5:
Evaluate 3x2+1 when x =4
Solution:
Given 3x2+1 when x =4
Here we need to substitute the value of x = 4 in the given equation
3x2+1 = 3 * (4)2 + 1
= 3 * 16 +1
= 48 + 1
= 49.
Example 6:
Evaluate 4(x+1) -2 when x =3
Solution:
Given 4(x+1) - 2 when x =3
Here we need to substitute the value of x = 3 in the given equation
4(x+1) - 2 = 4(3 + 1) - 2
= 4(4) - 2
= 16 - 2
= 14
Example 7:
Evaluate 10(2x+1) -3 when x = 4
Solution:
Given 10(2x+1) - 3 when x = 4
Here we need to substitute the value of x = 4 in the given equation
10(2x+1) - 3 = 20x + 10 - 3
= 20x + 7
Example 8:
Evaluate 6(x+1) -3 when x =5
Solution:
Given 6(x+1) - 3 when x =5
Here we need to substitute value of x = 5 in the given equation
6(x+1) - 3 = 6(5 + 1) - 3
= 6(6) - 3
= 36 - 3
= 33
I like to share this math problems 5th grade and Algebra Variables with you all through my blog.