Functions in algebra 2
Introduction :
Function is one of the subtopics in algebra 2. Each input which relates to only one output is known as function. In general, functions can be expressed as f(x). The algebraic expression deals with variables, the variable are represents by alphabetic letters.
In algebra 2 numbers are constant, algebraic expression may include real number, Simplify Complex Numbers , and polynomials. Functions in algebra 2 may include terms p(y), q(y).
For example:
Functions in algebra 2 may be described in this form p(y) = 2y2+3y + 4. In this function we need to find the function variable y.
Problem using the functions in algebra 2
Simplify using the square functions in algebra 2.
Problem 1:
p(x) = x2 +2x +14 find the p(5).
Solution :
Find the function p(5). Here substitute the value 5 to the variable.
p(x) = x2 +2x +14 find the f(5).
The value of x is 5 is given
p(5) = 52 +2*5 +14
p(5) = 25 +10 +14 In this step 52 is 25 it is calculate and 2*5 is 10 be added
p(5) = 49
The functions in algebra 2 p(5) = x2 +2x +14 find the p(5) is 49.
Problem2:
q(x) = x2 +6x +25 find the q(4).
Solution :
Find the function q(4). Here substitute the value 4 to the variable.
q(x) = x2 +6x +25 find the f(4).
The value of x is 4 is given
q(4) = 42 +6*4 +25
q(4) = 16 +24+25.
q(4) = 62
The answer is, q(4) = 62.
Functions in algebra 2 problems using the cubic functions
Problems1: using the cubic functions algebra 2:
f(x) = x3 +2x2 + 2x + 4 find the functions algebra 2 of f(2).
Solution
Find the function f(2). Here substitute the value 2 to the variable.
f(x) = x3 +2x2 + 2x + 4 find the f(2).
Here the value of x is given as 2
f(2) = 23 + 2*22 + 2*2 +4
f(2) = 8 +8+ +4 +4 In this step 23 is calculated as 8 and 2 square is 4
f(2) = 40.
The functions algebra 2 f(x) = x3 +2x2 + 2x + 4 find the f(2) = 40.
Problems 2:
f(x) = 2x3 +4x2 + 3x + 24 find the functions algebra 2 of f(4).
Solution
Find the function f(4). Here substitute the value 4 to the variable.
f(x) = 2x3 +4x2 + 3x + 24 find the f(4).
Here the value of x is given as 4
f(4) = 2*43 + 4*42 + 3*4 +24
f(4) = 128 +64+12 +24
f(4) = 228
The functions algebra 2 f(x) = 2x3 +4x2 + 3x + 24 find the f(4) = 228.
Function is one of the subtopics in algebra 2. Each input which relates to only one output is known as function. In general, functions can be expressed as f(x). The algebraic expression deals with variables, the variable are represents by alphabetic letters.
In algebra 2 numbers are constant, algebraic expression may include real number, Simplify Complex Numbers , and polynomials. Functions in algebra 2 may include terms p(y), q(y).
For example:
Functions in algebra 2 may be described in this form p(y) = 2y2+3y + 4. In this function we need to find the function variable y.
Problem using the functions in algebra 2
Simplify using the square functions in algebra 2.
Problem 1:
p(x) = x2 +2x +14 find the p(5).
Solution :
Find the function p(5). Here substitute the value 5 to the variable.
p(x) = x2 +2x +14 find the f(5).
The value of x is 5 is given
p(5) = 52 +2*5 +14
p(5) = 25 +10 +14 In this step 52 is 25 it is calculate and 2*5 is 10 be added
p(5) = 49
The functions in algebra 2 p(5) = x2 +2x +14 find the p(5) is 49.
Problem2:
q(x) = x2 +6x +25 find the q(4).
Solution :
Find the function q(4). Here substitute the value 4 to the variable.
q(x) = x2 +6x +25 find the f(4).
The value of x is 4 is given
q(4) = 42 +6*4 +25
q(4) = 16 +24+25.
q(4) = 62
The answer is, q(4) = 62.
Functions in algebra 2 problems using the cubic functions
Problems1: using the cubic functions algebra 2:
f(x) = x3 +2x2 + 2x + 4 find the functions algebra 2 of f(2).
Solution
Find the function f(2). Here substitute the value 2 to the variable.
f(x) = x3 +2x2 + 2x + 4 find the f(2).
Here the value of x is given as 2
f(2) = 23 + 2*22 + 2*2 +4
f(2) = 8 +8+ +4 +4 In this step 23 is calculated as 8 and 2 square is 4
f(2) = 40.
The functions algebra 2 f(x) = x3 +2x2 + 2x + 4 find the f(2) = 40.
Problems 2:
f(x) = 2x3 +4x2 + 3x + 24 find the functions algebra 2 of f(4).
Solution
Find the function f(4). Here substitute the value 4 to the variable.
f(x) = 2x3 +4x2 + 3x + 24 find the f(4).
Here the value of x is given as 4
f(4) = 2*43 + 4*42 + 3*4 +24
f(4) = 128 +64+12 +24
f(4) = 228
The functions algebra 2 f(x) = 2x3 +4x2 + 3x + 24 find the f(4) = 228.