High School Math
Introduction :
The high school has some math contents which can be stated as probability, statistics and geometry concepts. In this we can see some of the math concepts which can be studied in high school. Some important methods can also be stated in below math problems for high school math. We are going to see it with more details from the following examples.
High School Math Problem 1:
The followings are some of the high school math problems.
Solution:
(x2+ x + 1) / (x2 + 8x + 15) = 1 + (8x + 15) / (x2 + 8x + 15) ----> (1)
Let (8x + 15) / (x2 + 8x + 15) = A / (x + 3 )+ B / (x + 5)
8x + 15 = A(x + 3) + B(x + 5)
By putting x = -5,
-2A = -40+15
-2A = -25
A = `25/2`
By putting x = -3,
2B = -24 +15
2B = -9
B =` -9/2`
Therefore, (x2 + x +1) / (x2 + 8x + 15) = `25/2` / (x + 3) - `9/2` / (x + 5)
`rArr` (x2 + x +1) / (x2 + 8x + 15) = (1 + `25/2` ) / (x + 3) - `9/2` /(x + 5)
Solution:
By using the associative and distributive properties in them,
we obtain
(7x4 – 2x2 + 5x + 3) + (6x3 – 6x2 + 3x – 1) = 7x4 + 6x3 – 2x2 – 6x2 + 5x + 3x + 3 – 1
= 7x4 + 6x3 – (2 + 6) x2 + (5 + 3) x + 2
= 7x4 + 6x3 – 8x2 + 8x + 2
Solution:
2x + y = 6
y = 6 - 2x
Put x = 0 & we get y = 6
Then x = 1, y = 6 - 2 = 4
x = 2, y = 6 - 4 = 2
x = 3, y = 6 - 6 = 0
High School Math Problem 2:
The followings are some of the high school math problems.
Solution:
Total number of boys in town is 3000
Total number of girls in town is 2500
Total number of persons in the town = Total number of boys + Total number of girls
=3000 + 2500
= 5500
Divide total number of boys by total number of persons in the town
= `3000 / 5500`
= `6/11`
Therefore` 6/11 ` of the towns are boys.
Solution:
The given function are f(x) = 4x5 - 5x2 + 8x.
We can differentiate the given function with respect to x, then we get
f' (x) = (4 * 5)x4 - (2 * 5)x + 8
= 20x4 - 10x + 8
Answer:
The final answer is 20x4 - 10x + 8.
The high school has some math contents which can be stated as probability, statistics and geometry concepts. In this we can see some of the math concepts which can be studied in high school. Some important methods can also be stated in below math problems for high school math. We are going to see it with more details from the following examples.
High School Math Problem 1:
The followings are some of the high school math problems.
- Partial Fraction:
Solution:
(x2+ x + 1) / (x2 + 8x + 15) = 1 + (8x + 15) / (x2 + 8x + 15) ----> (1)
Let (8x + 15) / (x2 + 8x + 15) = A / (x + 3 )+ B / (x + 5)
8x + 15 = A(x + 3) + B(x + 5)
By putting x = -5,
-2A = -40+15
-2A = -25
A = `25/2`
By putting x = -3,
2B = -24 +15
2B = -9
B =` -9/2`
Therefore, (x2 + x +1) / (x2 + 8x + 15) = `25/2` / (x + 3) - `9/2` / (x + 5)
`rArr` (x2 + x +1) / (x2 + 8x + 15) = (1 + `25/2` ) / (x + 3) - `9/2` /(x + 5)
- Polynomial:
Solution:
By using the associative and distributive properties in them,
we obtain
(7x4 – 2x2 + 5x + 3) + (6x3 – 6x2 + 3x – 1) = 7x4 + 6x3 – 2x2 – 6x2 + 5x + 3x + 3 – 1
= 7x4 + 6x3 – (2 + 6) x2 + (5 + 3) x + 2
= 7x4 + 6x3 – 8x2 + 8x + 2
- Solving Linear Equations:
Solution:
2x + y = 6
y = 6 - 2x
Put x = 0 & we get y = 6
Then x = 1, y = 6 - 2 = 4
x = 2, y = 6 - 4 = 2
x = 3, y = 6 - 6 = 0
High School Math Problem 2:
The followings are some of the high school math problems.
- Word Problem:
Solution:
Total number of boys in town is 3000
Total number of girls in town is 2500
Total number of persons in the town = Total number of boys + Total number of girls
=3000 + 2500
= 5500
Divide total number of boys by total number of persons in the town
= `3000 / 5500`
= `6/11`
Therefore` 6/11 ` of the towns are boys.
- Differentiation value problem:
Solution:
The given function are f(x) = 4x5 - 5x2 + 8x.
We can differentiate the given function with respect to x, then we get
f' (x) = (4 * 5)x4 - (2 * 5)x + 8
= 20x4 - 10x + 8
Answer:
The final answer is 20x4 - 10x + 8.