Pre algebra functions
Introduction
Pre algebra function is main branch in mathematics deals with finding unknown variable from the given expression with the help of known values. The algebraic expressions contains variables are represented alphabetic letters.
In pre algebra functions, numbers are consider as constants, algebraic expression may include real number, complex number , and polynomials. Pre algebra functions may includes in the functions of f(x), p(x),… to find the x value in pre algebra functions.
For example:
The pre algebra functions in f(x) =3x2+3x+4. In this function we need to find the function 4.
Pre algebra functions using square equations
Problem1: pre algebra functions finding the x variable in the square equations f(x) = x2 +2x +4 find the f(2).
Solution :
Given the function of f(x) there is x value is given find the pre algebra functions
f(x) = x2 +2x +8 find the f(3).
The value of x is 3 is given
f(3) = 32 +2*3 +8
f(3) = 9 +6 +8 In this step 2 square is 4 it is calculate and 2*2 is 4 be added
f(3) = 23
Here pre algebra functions of f(3) is 23.
Problem2: pre algebra functions finding the x variable in the square equations f(x) = x2 +5x +4 find the f(5).
Solution :
Given the function of f(x) there is x value is given find the pre algebra functions
f(x) = x2 +5x +4 find the f(5).
The value of x is 5 is given
f(5) = 52 +5*5 +4
f(5) = 25 + 25 +4 In this step 5 square is 25, and 5*5 is 25 be added to the function f(5).
f(5) = 54
Here pre algebra functions of f(5) is 54.
Pre algebra problems functions using the cubic functions
Problem 1: pre algebra functions finding the x variable in the cubic equation f(x) = x3 +2x2 + 2x + 4 find the function 2 algebra of f(2).
Solution
Given the function of f(x) there is x value is given find the pre algebra functions
f(x) = x3 +2x2 + 2x + 4 find the f(2).
Here the value of x is given as 2
f(2) = 23 + 2*22 + 2*2 +4
f(2) = 8 +8+ +4 +4 In this step 23 is calculated as 8 and 2 square is 4
f(2) = 40.
The pre algebra functions of the f(x) = x3 +2x2 + 2x + 4 find the f(2) = 40.
Problem 2: pre algebra functions finding the x variable in the cubic equation f(x) = x3 +2x2 + 2x + 4 find the function 2 algebra of f(2).
Solution
Given the function of f(x) there is x value is given find pre algebra functions
f(x) = 2x3 +4x2 + 5x + 24 find the f(3).
Here the value of x is given as 3
f(3) = 2*33 + 4*32 + 5*3 +24
f(3) = 54 +36+15 +24 In this step 33 is calculated as 27 and multiplied by 2 we get as 54.Then the 32 is 9 and multiplied by 4 we get 36.
f(3) =129
The pre algebra functions of f(x) = 2x3 +4x2 + 5x + 4 find the f(3) = 129.
Pre algebra function is main branch in mathematics deals with finding unknown variable from the given expression with the help of known values. The algebraic expressions contains variables are represented alphabetic letters.
In pre algebra functions, numbers are consider as constants, algebraic expression may include real number, complex number , and polynomials. Pre algebra functions may includes in the functions of f(x), p(x),… to find the x value in pre algebra functions.
For example:
The pre algebra functions in f(x) =3x2+3x+4. In this function we need to find the function 4.
Pre algebra functions using square equations
Problem1: pre algebra functions finding the x variable in the square equations f(x) = x2 +2x +4 find the f(2).
Solution :
Given the function of f(x) there is x value is given find the pre algebra functions
f(x) = x2 +2x +8 find the f(3).
The value of x is 3 is given
f(3) = 32 +2*3 +8
f(3) = 9 +6 +8 In this step 2 square is 4 it is calculate and 2*2 is 4 be added
f(3) = 23
Here pre algebra functions of f(3) is 23.
Problem2: pre algebra functions finding the x variable in the square equations f(x) = x2 +5x +4 find the f(5).
Solution :
Given the function of f(x) there is x value is given find the pre algebra functions
f(x) = x2 +5x +4 find the f(5).
The value of x is 5 is given
f(5) = 52 +5*5 +4
f(5) = 25 + 25 +4 In this step 5 square is 25, and 5*5 is 25 be added to the function f(5).
f(5) = 54
Here pre algebra functions of f(5) is 54.
Pre algebra problems functions using the cubic functions
Problem 1: pre algebra functions finding the x variable in the cubic equation f(x) = x3 +2x2 + 2x + 4 find the function 2 algebra of f(2).
Solution
Given the function of f(x) there is x value is given find the pre algebra functions
f(x) = x3 +2x2 + 2x + 4 find the f(2).
Here the value of x is given as 2
f(2) = 23 + 2*22 + 2*2 +4
f(2) = 8 +8+ +4 +4 In this step 23 is calculated as 8 and 2 square is 4
f(2) = 40.
The pre algebra functions of the f(x) = x3 +2x2 + 2x + 4 find the f(2) = 40.
Problem 2: pre algebra functions finding the x variable in the cubic equation f(x) = x3 +2x2 + 2x + 4 find the function 2 algebra of f(2).
Solution
Given the function of f(x) there is x value is given find pre algebra functions
f(x) = 2x3 +4x2 + 5x + 24 find the f(3).
Here the value of x is given as 3
f(3) = 2*33 + 4*32 + 5*3 +24
f(3) = 54 +36+15 +24 In this step 33 is calculated as 27 and multiplied by 2 we get as 54.Then the 32 is 9 and multiplied by 4 we get 36.
f(3) =129
The pre algebra functions of f(x) = 2x3 +4x2 + 5x + 4 find the f(3) = 129.